Question

In the given figure, $\angle$ DBC$={22}^o$ and $\angle$ CB$={78}^o$ then $\angle$BAC is equal to

• A. ${90}^o$
• B. ${80}^o$
• C. ${78}^o$
• D. ${22}^o$

Answer 1

The correct option is B ${80}^o$

In $\Delta$BDC, $\angle D={180}^o-({22}^o+{78}^o)$
$={180}^o-{100}^o={80}^o$
$\therefore \angle BAC={80}^o$
(Angle in the same segment).