In the given figure, AOB is a straight line and the ray OC stands on it.
If ∠AOC = (2x − 10)° and ∠BOC = (3x + 20)°, find the value of x.
Also, find ∠AOC and ∠BOC

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Solution

By linear pair property:
∠AOC + ∠BOC= 180°
(2x-10)° + (3x+20)° = 180° (given)
5x + 10 =180
5x = 170
x = 34
∴ ∠AOC =(2x-10)° = (2×34-10)° = 58°
∠BOC = (3x+20)° = (3×34+20) °= 122°

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In the given figure, AOB is a straight line and the ray OC stands on it. If ∠AOC = (2x − 10)° and ∠BOC = (3x + 20)°, find the value of x. Also, find ∠AOC and ∠BOC

By linear pair property:∠AOC + ∠BOC= 180°(2x-10)° + (3x+20)° = 180° (given)5x + 10 =1805x = 170x = 34∴ ∠AOC =(2x-10)° = (2×34-10)° = 58° ∠BOC = (3x+20)° = (3×34+20) °= 122°

In the given figure, AOB is a straight line and the ray OC stands on it.
If ∠AOC = (2x − 10)° and ∠BOC = (3x + 20)°, find the value of x.
Also, find ∠AOC and ∠BOC

By linear pair property:
∠AOC + ∠BOC= 180°
(2x-10)° + (3x+20)° = 180° (given)
5x + 10 =180
5x = 170
x = 34
∴ ∠AOC =(2x-10)° = (2×34-10)° = 58°
∠BOC = (3x+20)° = (3×34+20) °= 122°