Question

In the given figure, AOBCA represent a quadrant of area 9.625 $c{m}^2$. Calculate the area of the shaded portion.

Answer 1

In the given figure, $DOA$ is a triangle with base $3.5cm$ and altitude $2cm$.

It is given that the area of the quadrant $AOBCA$ is $9.625c{m}^2$.

To find out: Area of the shaded region.

Area of the shaded region $=$ Area of quadrant $AOBCA-$ Area of $△DOA$

We know that, area of a triangle $=\frac{1}{2}\times b\times h$

$\therefore$ Area of $△DOA=\frac{1}{2}\times 3.5\times 2=3.5c{m}^2$

$\therefore$ Area of the shaded region $=9.625-3.5=6.125c{m}^2$

Hence, the area of the shaded region is $6.125c{m}^2$.