In the given figure, AP and AQ are the tangents drawn to a circle from a point A outside the circle. If ∠PAQ = 50∘ then, find ∠OPQ.
A
100∘
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B
12.5∘
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C
50∘
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D
25∘
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Solution
The correct option is D25∘ By theorem : If two tangents AP and AQ are drawn to a circle with centre O from an external point A, then ∠PAQ= 2∠OPQ= 2∠OQP
Given : ∠PAQ = 50∘ so, ∠OPQ = ∠PAQ2 ⇒∠OPQ = 50∘2 ⇒∠OPQ = 25∘