Question

In the given figure, BD =DC and $\angle$DBC = ${30}^0$. Find the measure of $\angle$ BAC if O is centre of the circle.

Answer 1

$BD=DC$

$\Rightarrow \measuredangle BCD=30°$

$\therefore \measuredangle BDC=120°$

$\Rightarrow \measuredangle BAC=60°$ (Opposite $\measuredangle$s of cyclic quadrilateral)