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Question

In the given figure chord AB extended meets tangent DC at C. If AB = 7cm and BC =9 cm and area of CBD=18cm2,

then area of CAD= ______


A

16 cm2

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B

24 cm2

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C

32 cm2

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D

64 cm2

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Solution

The correct option is C

32 cm2






CD is a tangent to the circle (given)

CD2=CB×CA

CD2=9×16

CD = 12cm

Hence, BDC=DAB (angles in the alternate segment are equal)

CDBCAD (AA similarity)

CDB/CAD=BC2CD2

18CAD=(912)2

18CAD=(34)2

18CAD=(916)

CAD=32cm2


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