Applying Pythagoras theorem for ΔPQR, we obtain PR2 = PQ2 + QR2 (13 cm)2 = (12 cm)2 + QR2 169 cm2 = 144 cm2 + QR2 25 cm2 = QR2 QR = 5 cm tan P − cot R ...

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Standard X

Mathematics

Opposite & Adjacent Sides in a Right Angled Triangle

find tan P - ...

Question

In the given figure find tan P − cot R

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Solution

Applying Pythagoras theorem for ΔPQR, we obtain

PR² = PQ² + QR²

(13 cm)² = (12 cm)² + QR²

169 cm² = 144 cm² + QR²

25 cm² = QR²

QR = 5 cm

tan P − cot R =

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In the given figure find tan P − cot R

Applying Pythagoras theorem for ΔPQR, we obtain PR2 = PQ2 + QR2 (13 cm)2 = (12 cm)2 + QR2 169 cm2 = 144 cm2 + QR2 25 cm2 = QR2 QR = 5 cm tan P − cot R =

Applying Pythagoras theorem for ΔPQR, we obtain

PR² = PQ² + QR²

(13 cm)² = (12 cm)² + QR²

169 cm² = 144 cm² + QR²

25 cm² = QR²

QR = 5 cm

tan P − cot R =