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Question

In the given figure, find the value of BAC. ΔDEF is equilateral, CBA=40, FEC=50 and DE is parallel to BC. [4 MARKS]

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Solution

Steps: 3 Marks
Result: 1 Mark

Given DEBC,CBA=40

ADE=CBA=40 [corresponding angle]

Since, ΔDEF is equilateral

DEF=60

FEC=50 (Given)
AED=180(50+60) (Angles on a straight line)
= 70
Consider ΔADE ,

AED=70 & ADE=40

ADE+AED+DAE=180 [Angle sum property]

DAE=180(70+40)=70.

BAC=DAE=70.


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