Question

In the given figure, if $\angle APD$ = (3x + 15)° and $\angle CPB$ = (4x - 5)°, then x = ___.

• A.

  ${15}^{\circ }$

• B.

  ${25}^{\circ }$

• C.

  ${20}^{\circ }$

• D.

  ${36}^{\circ }$

Answer 1

The correct option is C

${20}^{\circ }$

$\angle APD$ = $\angle BPC$ .......(vertically opposite angles) $\Rightarrow 3x+15=4x-5$ $\Rightarrow 15+5=4x-3x$ $\Rightarrow 20=x^{\circ }$ $\Rightarrow x={20}^{\circ }$