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Question

In the given figure, if AO = BO and OC = OD, then, ΔAOD ΔBOC by __ congruence rule.


Solution

In ΔAOD and ΔBOC, we have,

OA = OB (given)

OD = OC (given)

AOD = BOC (vertically opposite angles)

Therefore, ΔAOD  ΔBOC (by S.A.S. congruence condition)

Since AOD and BOC are the included angles for sides OA & OD and OB & OC respectively, we have the triangles congruent by using S.A.S. congruence rule.

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