In the given figure- m-1 nbsp- - nbsp-m-2 nbsp- - nbsp-m-3 nbsp- - 2 kg- Then- just after cutting string connecting nbsp-m-2 and m-3 nbsp- Acceleration of nbsp-m-2 is g-2 upwards-Acceleration of nbsp-m-1 is zero-Acceleration of nbsp-m-2 is zero-Acceleartion of nbsp-m-3 is zero-

The correct option is B Acceleration of nbsp;m_1 is zero. After cutting string connecting m_2 and m_3 , T=0 So, a_3= g(downwards) a_2 = g(upwards) a_1=0 ...

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Byju's Answer

Standard XII

Physics

Free Body Diagrams

In the given ...

Question

In the given figure, $m_{1}$ = $m_{2}$ = $m_{3}$ = 2 kg. Then, just after cutting string connecting $m_{2}$ and $m_{3}$

Acceleration of

m_{2}

is zero.

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Acceleartion of

m_{3}

is zero.

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Acceleration of

m_{2}

is g/2 upwards.

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Acceleration of

m_{1}

is zero.

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Solution

The correct option is D Acceleration of $m_{1}$ is zero.

After cutting string connecting $m_{2}$ and $m_{3}$ , $T = 0$
So,
$a_{3} = g$ (downwards)
$a_{2} = g$ (upwards)
$a_{1} = 0$

Suggest Corrections

Similar questions

Q. In the given figure,

m_{1}

m_{2}

m_{3}

= 2 kg. Then, just after cutting string connecting

m_{2}

and

m_{3}

Q. In the given figure,

m_{1}

m_{2}

m_{3}

= 2 kg. Then, just after cutting string connecting

m_{2}

and

m_{3}

Q. From the given system, just after cutting the string connecting

m_{4}

and ground, (here

(m_{1} + m_{2}) > (m_{3} + m_{4})

)

Q. For the given figure List - I gives acceleration of blocks of masses

m_{1}, m_{2}, m_{3} & m_{4}

and List - II gives their magnitudes. Here

m_{1} = m_{2} = 2 m

and

m_{3} = m_{4} = m

\begin{matrix} List - I & List - II (I) a_{1} & (P) 2 g (II) a_{2} & (Q) g (III) a_{3} & (R) \frac{g}{2} (IV) a_{4} & (S) \frac{g}{4} (T) 0 (U) None \end{matrix}

Just after cutting string connecting

m_{1}

and

m_{2}

correct match for accelerations of blocks is

Three solids of masses $m_{1}, m_{2} a n d m_{3}$ are connected with weightless string in succession and are placed on a frictionless table. If the mass $m_{3}$ is dragged with a force T, the tension in the string between $m_{2}$ and $m_{3}$ is

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In the given figure, m1 = m2 = m3 = 2 kg. Then, just after cutting string connecting m2 and m3

The correct option is D Acceleration of m1 is zero. After cutting string connecting m2 and m3 , T=0 So, a3=g(downwards) a2=g(upwards) a1=0

In the given figure, $m_{1}$ = $m_{2}$ = $m_{3}$ = 2 kg. Then, just after cutting string connecting $m_{2}$ and $m_{3}$

The correct option is D Acceleration of $m_{1}$ is zero.

After cutting string connecting $m_{2}$ and $m_{3}$ , $T = 0$
So,
$a_{3} = g$ (downwards)
$a_{2} = g$ (upwards)
$a_{1} = 0$