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Question

In the given figure, O is a point in the interior of a triangle.

ABC, OD BC, OE AC and OF AB. Then,
AF2+BD2+CE2=AE2+CD2+BF2


Correct Answer
A
True
Your Answer
B
False

Solution

The correct option is A True
AF2+BD2+EC2=(OA2OF2)+(OC2OE2)+(OB2OD2)

=(OA2OE2)+(OC2OD2)+(OB2OF2)

=AE2+CD2+BF2.
 

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