In the given figure O is the center of the circle and ∠BAC = 25∘ , then the value of ∠ADB is :
∠CBA = 90∘ (Angle subtended by a diameter)
∠ACB + ∠CBA + ∠BAC = 180∘
∠ACB + 90∘ + 25∘ = 180∘
∠ACB = 65∘
But ∠ADB = ∠ACB (Angle subtended by the same chord)
Therefore ∠ADB = 65∘
In the given figure, O is the centre of a circle and ∠OAB=50∘. Then, ∠CDA=?
In the figure, O is the center of the circle & AB is the Tangent to it at point B. ∠BDC = 65o. Find ∠BAO.
Given that AB = AC and ∠BOC = 140∘ where O is the center of the circle. ∠ABC =?