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Question

In the given figure 'O' is the center of the circle. SP and TP are the two tangents at S and T respectively. SPT is 50, the value of SQT is:

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A

125°

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B

65°

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C

115°

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D

None of the above 

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Solution

The correct option is D

115°


OSP = OTP = 90

Therefore OSPT is cyclic

SPT + SOT =  180

50 + SOT =  180

SOT =  130

Outer SOT = 360 – 130 =  230

SQT = 12 outer SOT

SQT = 12 ×  230

SQT =  115


Mathematics

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