In the given figure, O is the centre of a circle and ∠ACB = 30°. Then, ∠AOB = ?
(a) 30°
(b) 15°
(c) 60°
(d) 90°
Figure

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Solution

(c) 60°
We know that the angle at the centre of a circle is twice the angle at any point on the remaining part of the circumference.
Thus, ∠AOB = (2 × ∠ACB) = (2 × 30°) = 60°

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In the given figure, O is the centre of a circle and ∠ACB = 30°. Then, ∠AOB = ? (a) 30° (b) 15° (c) 60° (d) 90° Figure

(c) 60° We know that the angle at the centre of a circle is twice the angle at any point on the remaining part of the circumference. Thus, ∠AOB = (2 × ∠ACB) = (2 × 30°) = 60°

In the given figure, O is the centre of a circle and ∠ACB = 30°. Then, ∠AOB = ?
(a) 30°
(b) 15°
(c) 60°
(d) 90°
Figure

(c) 60°
We know that the angle at the centre of a circle is twice the angle at any point on the remaining part of the circumference.
Thus, ∠AOB = (2 × ∠ACB) = (2 × 30°) = 60°