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Question

In the given figure, O is the centre of a circle and PQ is a diameter. If ∠ROS = 40°, find ∠RTS.

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Solution

It is given that O is the centre and ROS=40°

We have

In right angled triangle RQT we have

RQT+QTR+TRQ=180°20°+QTR+90°=180°QTR=70°

Hence, RTS=70°


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