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Question

In the given figure, O is the centre of a circle and PT is the tangent to the circle. If PQ is a chord such that QPT = 50o then POQ = ?

(a) 100o   (b) 90o  (c) 80o  (d) 75o


Solution

Angle OPQ = 90°-50°=40°
OP=OQ ( radii of circle) 
angleOPQ= angleOQP=40°
(equal opposite side have equal opposite angles) 

angle POQ =180°- angle OQP- angle OPQ
         = 180°-40°-40°=100°

option (A) 100° is correct answer 

Mathematics
Secondary School Mathematics X
Standard X

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