CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, O is the centre of a circle. If AOB=100 and AOC=90 then BAC=?

(a) 85

(b) 80

(c) 95

(d) 75

Open in App
Solution

(a) 85°

We have:
∠BOC + ∠BOA + ∠AOC = 360°
⇒ ∠BOC + 100° + 90° = 360°
⇒ ∠BOC = (360° - 190°) = 170°
∴ ∠BAC=1/2×∠BOC=1/2×170°=85°

flag
Suggest Corrections
thumbs-up
47
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction - concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon