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Question

In the given figure, O is the centre of the circle. AB is the tangent to the circle at the point P. If APQ = 58o then the measure of PQB is

(a) 32o  (b) 58o  (c) 122o  (d) 132o


Solution

We know that, <APO = 90° (As AB is the tangent)

Thus
<QPO = 90° - 58° = 32°


Now, in  triangle OPQ, OP = OQ (radii of the circle)
Therefore  <QPO = <OQP = 32°
Thus <PQB = <OQP = 32°

(a) 32° is correct answer 

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