In the given figure $O$ is the centre of the circle. The angle subtended by the arc $B C D$ at the centre is $140^{\circ}$ . Find $∠ B A D$ .

40^{\circ}

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50^{\circ}

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20^{\circ}

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70^{\circ}

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Solution

The correct option is D $70^{\circ}$
$W e h a v e c i r c l e w i t h c e n t r e 0 ∠ B O D i s c e n t r a l a n g l e ∠ B O D = 140 (G i v e n) 2 ∠ B A D = ∠ B O D \Rightarrow ∠ B A D = \frac{1}{2} ∠ B O D \Rightarrow ∠ B A D = \frac{140}{2} = 70$

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In the given figure O is the centre of the circle. The angle subtended by the arc BCD at the centre is 140∘. Find ∠BAD.

The correct option is D 70∘Wehavecirclewithcentre0∠BODiscentralangle∠BOD=140(Given)2∠BAD=∠BOD⇒∠BAD=12∠BOD⇒∠BAD=1402=70

In the given figure $O$ is the centre of the circle. The angle subtended by the arc $B C D$ at the centre is $140^{\circ}$ . Find $∠ B A D$ .

The correct option is D $70^{\circ}$
$W e h a v e c i r c l e w i t h c e n t r e 0 ∠ B O D i s c e n t r a l a n g l e ∠ B O D = 140 (G i v e n) 2 ∠ B A D = ∠ B O D \Rightarrow ∠ B A D = \frac{1}{2} ∠ B O D \Rightarrow ∠ B A D = \frac{140}{2} = 70$