Question

In the given figure, $OACB$ is a quadrant of a circle with center $O$ and radius $3.5cm$. If $OD=2cm$, find the area of the
Quadrant $OACB$

Answer 1

Radius of Circle, $OA=OB=3.5cm$
$OD=2cm$
i) Area of quadrant of a circle
ii) Area of the shaded region
i) Area of quadrant $\left(OACB\right)$ of a circle
$r=3.5cm,\theta ={90}^o$
$\therefore$ Area $=\frac{\theta }{360}\times \pi r^2$
$=\frac{90}{360}\times 3.14\times (3.5{)}^2$
$=\frac{1}{4}\times 3.14\times 12.25$
$=9.61sq.cm$