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Question

In the given figure, PQ = 24 cm, PR = 7 cm and O is the centre of the circle. Find the area of the shaded region. [Take π=3.14]

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Solution

For the given diagram..

QPR=90 because it is half the reflex of QOR which is 180

By pythagoras theroem....
QR2=QP2+RP2
= 242+72
= 576 + 49 = 625
QR = 25cm
radiusofthecircle=252
area of the shaded region = area of semicircle - area of triangle PQR

= πr22(PR×PQ2)


=(22×25×252×2×2×7)(7×242)
= (11×25×252×2×7)(7×12)
= 68758484
= 452328cm2
=161.54cm2


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