In the given figure, PT touches a circle whose centre is O at R. Diameter SQ produced meets PT at P. If ∠SPR=x∘ and ∠QRP=ycirc, then which of the following statements relate x and y?
PT is a tangent to the circle (given)
∠QRP=∠QSR=y∘ (angle in the alternate segment are equal)
QS is diameter of the circle (given)
∠QRS=90∘ (angle in the semi circle)
In △PSR,x+y+90∘+y=180∘ (sum of angles of a triangle)
∴x+2y=90∘ Hence (A)