CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

In the given figure two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that θ is so small that tan θsin θ, then for equilibrium x is equal to

 
  1. (qL22πϵ0mg)1/3
  2. (q2L2πϵ0mg)1/3
  3. (q2L24πϵ0mg)1/3
  4. (q2L4πϵ0mg)1/3


Solution

The correct option is B (q2L2πϵ0mg)1/3

In equilibrium Fe=T sin θ ....... (i)
mg=T cos θ ........ (ii)
tan θ=Femg=q24πϵ0x2×mg also tan θsin θ=x2L
Hence x2L=q24πϵ0mgx=(q2L2πϵ0mg)1/3

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image