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Question

In the given image, segment AB has been divided in the ratio 3:2. This is done by
1. Draw any ray AX making acute angle with AB.
2. Draw a ray BY parallel to AX by making ABY=BAX
3. Locate the points A1,A2,A3...A3 on AX and B1,B2 on BY such that AA1=A1A2=BB1=B1B2
4. Join A3B2by using which of the properties of parallel lines?

A
Corresponding angle are equal
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B
Alternate interior angles are equal
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C
Co-interior angle are supplementary
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D
Perpendicular bisector theorem
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Solution

The correct option is B Alternate interior angles are equal

Here we use alternate interior angles are equal then the lin4es are parallel and XAB=ABY as AX parallel to BY.

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