Question

In the graph between $\sqrt{v}$ and Z for the Moseley's equation, the intercept OX is $-1$ on $\sqrt{v}$ axis. What will be in frequency when atomic number (Z) is $51$?

• A. 50 Hz
• B. 100 Hz
• C. 2500 Hz
• D. None

Answer 1

The correct option is C 2500 Hz

Moseley's equation is : $\sqrt{v}=a(z-b)=az-ab$
Given that, $ab=1,a=\tan {45}^{\circ }=1\therefore \sqrt{v}=51-1=50\Rightarrow v=2500Hz$