In the graph shown the displacement of the body is $5$ seconds will be

60 m

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40 m

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80 m

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100 m

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Solution

The correct option is B $80 m$
Displacement = $(\frac{d x}{d t}) \times d t = \int d x$
= Area under V-t curve
$= A_{1} + A_{2} + A_{3} + A_{4} + A_{5}$
$= \frac{1}{2} [40 - 20] \times (2 - 0) + (3 - 2) \times 20 + \frac{1}{2} \times 20 \times (4 - 3) + \frac{1}{2} \times (- 20) \times (5 - 4) + 2 \times 20$
Disp = $20 + 20 + 10 - 10 + 40 = 40 m + 40 m$
$= 80 m$

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