Question

# In the molecule $$CH_3C \equiv C-CH = CH_2$$, the maximum number of carbon atoms arranged linearly is:

A
2
B
3
C
4
D
5

Solution

## The correct option is C 2$$sp$$ hybridized carbon atoms are linear in shape.$$CH_3-C\equiv CH-CH=CH_2$$In this compound, $$2$$ carbons are linearly arranged as they are $$sp$$ hybridized. So the answer is $$2$$ .Chemistry

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