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Question

In the molecule $$CH_3C \equiv C-CH = CH_2$$, the maximum number of carbon atoms arranged linearly is:


A
2
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B
3
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C
4
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D
5
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Solution

The correct option is C 2
$$sp$$ hybridized carbon atoms are linear in shape.
$$CH_3-C\equiv CH-CH=CH_2$$
In this compound, $$2$$ carbons are linearly arranged as they are $$sp$$ hybridized. So the answer is $$2$$ .

Chemistry

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