Question

In the part of a circuit shown, the potential difference $(V_G-V_H)$ between points G and H will be

• A. 0 V
• B. 15 V
• C. 7 V
• D. 3 V

Answer 1

Answer: (C)

7 V

Using Kirchhoff's junction law, we get current flowing through 1 $\Omega$ to be $2$ amp in the upward direction.

Using Kirchhoff's loop law between G and H :

$\therefore$ $V_G-2\left(4\right)+3-2\left(2\right)+2\left(1\right)-V_H=0$

$⟹$ $V_G-V_H=7$ V