In the preparation of $H N O_{3}$ , we get NO gas by catalytic oxidation of ammonia. The moles of NO produced by the oxidation of two moles of $N H_{3}$ will be :

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Solution

The correct option is B 2
In the preparation of $H N O_{3}$ , we get NO gas by catalytic oxidation of ammonia.In the below equation 4 moles of $N H_{3}$ produced 4 moles of $N O$ .So the moles of $N O$ produced by the oxidation of two moles of $N H_{3}$ will be2 moles.
$4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O$ .
Hence option A is correct.

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