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Algebraic Identities

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Question 49

In the question given below, fill in the blanks to make the statement true:

$103^{2} - 102^{2} =$ _ $\times (103 - 102) =$ _ .

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Solution

$(103 + 102), 205$
We have,
$103^{2} - 102^{2} = (103 + 102) (103 - 102) [∵ a^{2} - b^{2} = (a + b) (a - b)] = 205 \times 1 = 205$

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Algebraic Identities

Standard VIII Mathematics

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