Question

In the radioactive disintegration series ${}_{90}^{232}Th{\to }_{82}^{208}Pb$, involving $\alpha$ and $\beta$ decay, the total number of $\alpha$ and $\beta$ particles emitted as:

• A. $6\alpha$ and $6\beta$
• B. $6\alpha$ and $4\beta$
• C. $6\alpha$ and $5\beta$
• D. $5\alpha$ and $6\beta$

Answer 1

The correct option is B $6\alpha$ and $4\beta$

In radio-active distintegration of ${}_{90}^{232}Th{\to }_{82}^{208}Pb$ involving $\alpha$ and $\beta$ decay, the total number of $\alpha$ and $\beta$ particles emitted is $6\alpha$ and $4\beta$.