In the reacti...

Question

In the reaction between $C l_{2}$ and hot conc. NaOH, which is correct?

The oxidation number of

C l_{2}

changes from 0 to +5 and 0 to -1.

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C l_{2}

undergoes disproportionation.

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C l_{2}

undergoes self or auto redox change.

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All of these.

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Solution

The correct option is D All of these.
With hot concentrated alkali solutions it forms chlorates.
$6 N a O H + 3 C l_{2} \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$
0 -1 +5

$C l_{2}$ undergoes disproportionation.

Hence,option D is correct.

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