In the reaction between zinc and iodine, zinc iodide is formed. Which is being oxidised?

Zinc ions

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Iodide ioins

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Zinc atom

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Iodine

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Solution

The correct option is B Zinc atom
In the reaction between zinc and iodine, zinc iodide is formed. Zinc atom is being oxidised as an electro-negative element is added to it and iodine is reduced to $I^{-}$ .

$Z n$ + $I_{2}$ $\to$ $Z n I_{2}$

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Balance the equations

Q. Zinc upon reaction with steam forms zinc oxide and .

Write the balanced chemical equation for the following and identify the type of reaction in each case –
$(A) P o t a s s i u m b r o m i d e (a q) + B a r i u m i o d i d e (a q) \to P o t a s s i u m i o d i d e (a q) + B a r i u m b r o m i d e (s)$

$(B) Z i n c c a r b o n a t e (s) \to Z i n c o x i d e (s) + C a r b o n d i o x i d e (g)$

Q. During the disproportionation of iodine to iodide and iodate ions, the ratio of iodate and iodide ions formed in alkaline medium is:

Q. Chlor-zinc iodide (Schultz solution) stains

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In the reaction between zinc and iodine, zinc iodide is formed. Which is being oxidised?

The correct option is B Zinc atomIn the reaction between zinc and iodine, zinc iodide is formed. Zinc atom is being oxidised as an electro-negative element is added to it and iodine is reduced to I−.Zn+ I2 → ZnI2

The correct option is B Zinc atom
In the reaction between zinc and iodine, zinc iodide is formed. Zinc atom is being oxidised as an electro-negative element is added to it and iodine is reduced to $I^{-}$ .

$Z n$ + $I_{2}$ $\to$ $Z n I_{2}$