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Question

In the reaction 
C2O24+MnO4+H+Mn2++CO2+H2O  which is the reducing agent?
 


  1. C2O24

  2. MnO4

  3. Mn2+

  4. H+


Solution

The correct option is A

C2O24


C2O24+MnO4+H+Mn2++CO2+H2O

C2O24

2x + 4×(2)=2

2x=2+8

2x=6

x=+3

whereas in the product side Oxidation number of carbon = +4

That shows that it has donated one electron, thereby oxidizing others.

In this reaction C2O24 act as a reducing agent.

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