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Question

In the reaction, I2+2S2O232I+S4O26
equivalent weight of iodine is

A
12 of molecular weight
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B
Molecular weight
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C
14 of molecular weight
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D
None of these
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Solution

The correct option is A 12 of molecular weight
The oxidation number of iodine changes from 0 to -1. Since there are two iodine atoms in the iodine molecule, the n - factor for iodine is 2.
Equivalent wt of iodine=Molecular weight2

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