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Question

In the reaction PCl5PCl3+Cl2 the partial pressure of PCl3,Cl2 and PCl5 are 0.3, 0.2 and 0.6 atm respectively at equilibrium. If partial pressure of PCl3 and Cl2 was increased twice, what will be the partial pressure of PCl5 is in atm at new equilibrium condition:

A
0.3
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B
1.2
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C
2.4
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D
0.15
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Solution

The correct option is A 2.4
PCl5KpPCl3+Cl2

KC=[PCl3][Cl2][PCl5],

Equilibrium constant of reaction remain same.

KP=[PPCl3][PCL2][PPCl5]

KP=(0.3)(0.2)0.6=0.1,

Now as concentrations are doubled for PCl3 and Cl2

Kp=0.1=(0.6)(0.4)[PCl5]

PPCl5=2.4

Hence, the correct option is C.

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