In the rectangle ABCD, O is any point inside the rectangle. If area( ΔAOD) = 30 cm2 and area( ΔBOC) = 60 cm2, area of the rectangle ABCD is
Draw a line through O parallel to ADas shown.
Parallelogram APQD and triangle AOD are on same base AD and between same parallels.
So, Area of parallelogram APQD = 2 x Area of AOD
Area of APQD = 60cm2
Parallelogram PBCQ and triangle BOC are on same base BC and between same parallels.
So, Area parallelogram PBCQ = 2 x Area BOC
Area of PBCQ = 120cm2
Area of ABCD =Area (APQD)+Area (PBCQ)=180cm2