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Question

In the shown pulley-block system, strings are light. Pulleys are massless and smooth. System is released from rest. In 0.6 second: [Take g=10m/s2]
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A
Work done on 20kg block by gravity is 120J
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B
Work done on 20kg block by string is 20J
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C
Work done on 10kg block by gravity is 30J
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D
Work done on 10kg block by string is 20J
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Solution

The correct options are
A Work done on 20kg block by gravity is 120J
B Work done on 10kg block by gravity is 30J
C Work done on 20kg block by string is 20J
D Work done on 10kg block by string is 20J

2T10g=10a and 20gT=40a 30g=90a a=g/3

For (A): W=mgh=(20)(10)[12×g3×(0.6)2]=120J

For (B): T=(10g10a2)=(10g10g/32)=10(2g3)2=(1003)N

W=T×(h)=1003×610=20J

For (C): Wgravity=mg(h/2)=10×(10)(620)=30J

For (D): =+20J


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