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Question

In the Young’s double slit experiment apparatus shown in figure, the ratio of maximum to minimum intensity on the screen is 9. The wavelength of light used is λ,  then the value of y is


  1. λ Dd

  2. λ D2d

  3. λ D3d

  4. λ D4d


Solution

The correct option is C

λ D3d


ImaxImin=I1I2+1I1I212=91

or x+1x1=3      (x=I1I2)

 x=2

 I1I2=4

I1=4I2

i.e., if I2=I0

then I1=4I0

I0=4I0= cos2ϕ2

 ϕ=2π3

 (2πλ) (ydD)=2π3

 y=λD3d

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