In triangle ABC; ∠ A = 600, ∠ C = 400 and bisector of angle ABC meets side AC at point P. Show that BP= CP.
In triangle ABC, angle B = 35o, angle C = 65o and the bisector of angle BAC meets BC in P. Choose the correct descending order of AP, BP and CP
In triangle ABC; angle ABC = 900 and P is a point on AC such that ∠ PBC = ∠ PCB. Show that : BP = CP.
In Δ ABC, angle ABC is equal to twice the angle ACB, and bisector of angle ABC meets the opposite side at point P. Show that: (i) CB: BA =CP: PA (ii)AB × BC = BP × CA