In triangle ABC; angle ABC = 900 and P is a point on AC such that ∠ PBC = ∠ PCB. Show that : BP = CP.
given: ABC is a right angled triangle, right angled at B.
TPT: PA = PB
in the right angled triangle ABC,
therefore in the triangle ABP;
therefore PA = PB [since in a triangle sides opposite to equal angles are equal in length]