In triangle ABC, $∠ B = ∠ C . D a n d E$ are the mid points of AB and AC respectively.
Then, the value of $\frac{B E}{C D}$ is:

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2.5

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Solution

The correct option is B 1
Given, in $Δ A B C, ∠ B = ∠ C .$
D and E are the mid points of AB and AC re
In $Δ A B E a n d Δ A C D,$
AB = AC
(Sides opposite to equal angles of a triangle are equal.)
$\Rightarrow A D = A E$
(halves of equal sides are equal)
$∠ A = ∠ A$ (common angle)
$∴ Δ A B E ≅ Δ A C D$ (SAS rule)
$\Rightarrow C D = B E$ (CPCTC)
$∴ \frac{B E}{C D} = 1$

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