Question

# In △ABC, bisector of ∠A and ∠B intersect at point O. If ∠C=70o what is the value of ∠AOB?

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Solution

## In a triangle, the sum of interior angle =180∘Thus, in △ABC , ∠A+∠B+∠C=180∘∠C=70∘,Hence,∠A+∠B=130∘ Bisector of ∠A and∠B intersect at point O then ∠A2+∠B2=65∘∠OAB+∠OBA=65∘Now, in △OAB,∠OAB+∠OBA+∠AOB=180∘⇒∠AOB=115∘

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