Question

In $△ABC$, if AB =AC and $\angle B={50}^{\circ }$, then $\angle C$ is equal to

• A. ${40}^{\circ }$
• B. ${50}^{\circ }$
• C. ${80}^{\circ }$
• D. ${130}^{\circ }$

Answer 1

The correct option is B ${50}^{\circ }$

Given, in $△ABC$, AB = AC and $\angle B={50}^{\circ }$.


We know that angles opposite to equal sides of an isosceles triangle are equal.
$\Rightarrow \angle C=\angle B$ [angles opposite to equal sides ]
$\Rightarrow \angle C={50}^{\circ }[\because \angle B={50}^{\circ }(given\left)\right]$