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Question

In ABC,
sin(A+B2)= .

A
cos(C2)
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B
cos(C4)
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C
sin(C2)
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D
cos(C4)
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Solution

The correct option is A cos(C2)
In a triangle, sum of all the internal angles is 180.
A+B+C=180
A+B+C2=90
A+B2=90C2
sin(A+B2)=sin(90C2)

Since
sin(90θ)=cos θ

sin(A+B2)=sin(90C2)


sin(90C2)=cosC2

sin(A+B2)=cosC2

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