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Question

In PQR, PQ = 12 cm and PR = 13 cm. Q=90. Find the value of tan P - cot R.


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Solution


Given that, in PQR, PQ = 12 cm and PR = 13 cm.

Now, from Pythagoras' theorem,
PQ2+QR2=PR2
QR2=PR2PQ2
QR2=132122
QR2=169144=25
QR=25=5 cm

Now, tan P=opposite sideadjacent side=QRPQ=512
cot R=adjacent sideopposite side=QRPQ=512

tan Pcot R=512512=0


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