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Question

In triangle PQR, right angled at Q, if tanP=13 find the value of sinP+cosR+cosPsinR

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Solution

tanP=13
=tan30°
P=30°
In PQR,
P+Q+R=180°
30°+90°+R=180°
R=180°120°
Now, sinP+cosR+cosPsinR=sin30°+cos60°+cos30°sin60°
=12+12+32×32
=1+34
=74
Hence, the answer is 74.

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