Question

# In two separate collisions, the coefficients of restitution are e1 and e2 are in the ratio 3:1. In the first collision the relative velocity of approach is twice the relative velocity of separation, then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is :

A
1:6
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B
2:3
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C
3:2
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D
6:1
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Solution

## The correct option is D 6:1We know that: e=relative velocity after collisionrelative velocity before collisionGiven :e1e2=31,e1=12⇒(12)e2=31⇒e2=16So, the ration between relative velocity of approach and the relative velocity of separation in the second collision is 6:1.

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