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Question

In which of the following arrangements, the sequence is not strictly according to the property written against it?

A
CO2<SiO2<SnO2<PbO2: increasing oxidising power
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B
NH3<PH3<AsH3<SbH3: increasing basic strength
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C
HF<HCl<HBr<HI: increasing acid strength
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D
B < C < O < N: increasing first ionisation enthalpy
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Solution

The correct option is B NH3<PH3<AsH3<SbH3: increasing basic strength
(a) oxidising power:- ability to release one e
but o.p of SnO2 is than PbO2
Pb have 4 f which provides less hindrance attraction provided by its protons
PbO2 has tendency to gain e than to oxidise itself than SnO2
C<Si<Pb<Sn oxidising power
(b) Basic strength :- lone pair basic strength
Group 15
(c) Acidic strength:- More easy dissociation in H+A acidic strength.
(d) B<C<O<N
atomic number
charge in the order of Boron & oxygen.
Ans A

1431931_1030858_ans_1388dab31d2047b2ab44e2e75bedd0b5.png

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